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JH
Numerade Educator

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Problem 64 Hard Difficulty

Find the area of the region under the given curve from 1 to 2.

$ y = \dfrac{1}{x^3 + x} $

Answer

$\frac{3}{2} \ln 2-\frac{1}{2} \ln 5$

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Video Transcript

let's find the area of the region under the given curve from X equals one to two. So what they're asking for is theater girl from one to two of this function that'LL just be the area under the curve from wanted to And then we should do a partial freshen the composition here tto be able to evaluate this inaugural so we can rewrite that denominator. Now, this guy right here, this will not faster. If we just look at the Discriminate B squared minus four A. C will be negative. So this will not factor so we can write. This is ale Rex. That's what the author calls Case one and then we have B X plus C for the quadratic. And this is what the author calls Case three. It's got and multiply this equation on both sides by this term around here and then we can go ahead and combined term. So it's pulling X square. Here we have a plan B plus X. We just have CX and then a so comparing coefficients under left and right, we see a plus B must be zero c must be zero. They must be won. So we end up with It's right this out. April's one C equals zero, and by this over here be is negative one. Let's just go ahead and plug in these values for a B and C Hey into the right hand side over here and then we'LL evaluate this expression. Let's go to the next page. After plugging in a B and C, there's our inaugural. So for the second one, we can go ahead and he's a use up here, x squared, plus one and then do you over, too, so that may help you with this integral I won't actually use the use of here. So the first annual girl Natural log and then for the second minus one half you could see where the one half is coming from. Natural log X squared, plus one wanted to, and then just go ahead and plug in the end. Points in Simplify Natural law, too. One half Ellen five plus one half Ellen, too. And then we have three half combining those natural log of twos, and there's a final answer