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Find the areas bounded by the indicated curves.$$y=3 / x^{2}, y=0, x=2, x=3$$

$$A=\frac{1}{2}$$

Calculus 2 / BC

Chapter 26

Applications of Integration

Section 2

Areas by Integration

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we want to find the area found by the curves. Why equals three over x square Y equals zero X equals two and X equals three. So this question is challenging our understanding of applications of integration. Let's not appropriate definitions before proceeding. So the area between two curves is political components equals integral. A. To B Y. Two minutes by one dx for horizontal components A equals integral DVD extra minutes 20 Y. Thus, if we sketch this out, identify the relative bounds and curves to integrate underneath, we can solve if we sketch it out, we see that the area highlighted in yellow is are given region. Thus we see that it's easy enough to entertain this area by integrating from 2 to 33 or X square. That's our area is the interval from 2 to 33 over X squared dx or negative three over X. Evaluated from 2 to 3, negative 3/3 is negative, one plus 3/2 is three half. So we have the solution one half.

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