00:02
We want to find the area founded by the curves.
00:05
Y equals x square, y equals 2 minus x, and y equals 1.
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This question is challenging your understanding of how to apply integration for the purpose of areas derivation.
00:18
So, no appropriate definitions for the area between two curves.
00:21
For vertical components, it is a equals integral a to b, y, 2 minus y, d, d, x, y, 2 minus y, d, d .x.
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For horizontal components, it's a equals integral c to d x, 2 minus x, 1, d .d...