00001.
For x = 1, we substitute x = 1 into the function f(x):
\[f(1) = \sqrt{1^{3}+2 \cdot 1^{2}-6 \cdot 1+5} = \sqrt{2}\]
For x = 1.00001, we substitute x = 1.00001 into the function f(x):
\[f(1.00001) = \sqrt{(1.00001)^{3}+2 \cdot (1.00001)^{2}-6 \cdot
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