00:01
Hi there, so for this problem, we need to find the capacitance per unit length of two coaxial metal cylindrical tubes of radii a and b, as is shown in this figure.
00:13
So in this, for this problem, say that the charge on the inner cylinder is cube of a length out.
00:23
And the field is then given by gauss law.
00:26
So that states that the product between the electric field and the differential in area, that is the gauss law.
00:34
And we can take out the electric field out because it is a constant.
00:37
So we will have that this is the integral of the differential in area, which corresponds to the area.
00:43
So we know that the area of a cylindrical geometry is 2xx, which is the radius times else.
00:53
And this is equal to by gausslaw is equal to the enclosed charge divided by epsilon sub -0.
01:02
So if we solve for, we know that in this case, the enclosed charge corresponds to the charge q.
01:11
So if we solve for the electric field, we know that the electrode field is going to be the charge q divided by two times pye times epsilon sub -0 times the length l...