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Find the center and radius of each circle. (Hint: In Exercises 15 and $16,$ divide each side by a common factor)$$3 x^{2}+3 y^{2}-12 x-24 y+12=0$$
center: (2,4)$; r=4$
Precalculus
Algebra
Chapter 13
Nonlinear Functions, Conic Sections, and Nonlinear Systems
Section 2
The Circle and the Ellipse
Introduction to Conic Sections
An Introduction to Geometry
Functions
Systems of Equations and Inequalities
Missouri State University
Harvey Mudd College
Idaho State University
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way have the equation. Three X squared was three y squared minus 12 x minus 24. Why plus 12 equals zero. Let's first divide three out of everything. So we divide everything by three. We get expert post y squared minus four x minus eight wide plus four equals zero. Let's reorganize. So our exes are together, our wives are together and we're to move the constant to the right hand side by subtracting for the both sides. Now we can complete the square with both the exes and the wise half of negative four is negative. Two square is positive for to both sides, half of negative eight is negative. Four square plus 16 toe both sides That allows us to write the perfect square. Bino meals X minus two squared plus y minus four squared equals 16. Therefore, the center of the circle is at 24 and the radius is four weeks. Fourth, where is 16
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