Question
Find the center of mass of the lamina that has the given shape and density.$$y=x, x+y=6, y=0 ; \rho(x, y)=2 y$$
Step 1
The mass is given by the double integral of the density function over the region. The region is bounded by the curves $y=x$, $x+y=6$, and $y=0$. So, we have $$ M = \int_0^3 \int_y^{6-y} 2y \, dx \, dy. $$ Show more…
Show all steps
Your feedback will help us improve your experience
Amany Waheeb and 76 other Calculus 3 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find the center of mass of the lamina that has the given shape and density. $$ y=x^{2}, x=1, y=0 ; \rho(x, y)=x+y $$
Vector Calculus
Double Integrals
Find the center of mass of the lamina that has the given shape and density. $$ x=0, y=0,2 x+y=4 ; \rho(x, y)=x^{2} $$
Find the center of mass of the lamina that has the given shape and density. $$ y=|x|, y=3 ; \rho(x, y)=x^{2}+y^{2} $$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD