Question
Find the center of mass of the point masses lying on the $x$ -axis.$m_{1}=8, m_{2}=5, m_{3}=5, m_{4}=12, m_{5}=2$$x_{1}=-2, x_{2}=6, x_{3}=0, x_{4}=3, x_{5}=-5$
Step 1
The moment is equal to the sum of the product of each mass and its position. Mathematically, it can be represented as $M = m_1x_1 + m_2x_2 + m_3x_3 + m_4x_4 + m_5x_5$. Substituting the given values, we get: \[M = 8(-2) + 5(6) + 5(0) + 12(3) + 2(-5) = 40\] Show more…
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