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Find the centre and radius of the circles.$$(x+5)^{2}+(y-3)^{2}=36$$
Centre = (-5,3) radius =6
Precalculus
Chapter 11
Conic Sections
Section 1
Introduction
Introduction to Conic Sections
Johns Hopkins University
Campbell University
Piedmont College
Boston College
Lectures
07:16
In mathematics, a continuo…
04:09
03:08
Find the center and the ra…
01:21
00:40
Find the center and radius…
01:34
03:09
00:41
Give the center and radius…
01:39
01:17
00:59
Problem We are given the equation of the circle as X plus five whole square Plus Y -3 whole square equals two. 36 scan Britain has x minus off minus Fife World Square Plus, Why AM -3 Whole square equals two six square. The standard form of the equation of circle is nothing but x minus H. World square less. Why minus k Whole square equals two R squared, Comparing these three questions. We get the center is that it's common key. Just nothing but edges -5 Komaki is three and the radius There's nothing but six. That's it.
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