00:01
We need to find the change of basis matrix from b to c.
00:07
To do that first, we write the first vector of order basis b, which is negative 7, 4, and 4.
00:16
And then we write equal to, so we need to find a vector with three components, c1, c2, c3, that when it's multiplied by the vectors of ordered basis c, c, gives us the, or a vector i've written.
00:33
So what we do, we write c1 multiplied by the first vector, 1, 1, and 0, plus c2 is 0, 1, and 1.
00:45
And then c3, multiply, is 3, negative 1, negative 1.
00:52
Then here you have x, y, z, and x is equal to c1, multiple, y, x of the first vector, c2 multiply by the x of the second vector and c3 multiply by the x of the third vector and similarly for y and z so i write the system of equation which is c1 plus c3 c3 equals to negative 7 c1 plus c2 negative minus c3 is equal to 4 and then c2 minus c3 is equal to 4 and then c2 minus c3 is equal to 4 just we can rewrite this one c2 is equals to 4 plus c3 and replace it here then we have this is now for which we can solve it easily and we get c1 c2 and c3 equals to and 0 5 thid and negative 7th so the first vector relative to is c is 0 5.
02:18
So first we found the first column of the matrix we are looking for.
02:25
So we do the same for the second vector of the order basis b.
02:29
So i write it here.
02:31
The second vector is 4, 2, and negative 1.
02:37
Similarly, we write c1, 2, 1 ,0, plus c2 multiplied by 0, 1, and 1, plus c3, multiply, minus 3, negative 1, and 1.
02:59
I write the system of equations here.
03:02
We have c1 plus 3, c2, 3, equals to 4, c1, plus c2, minus c3 is supposed to 2, and c2.
03:20
Plus negative c3 equals to negative 1.
03:27
We can simplify here, say c2 equals to negative 1 plus c3, and then replace and solve for c1, c2, and c3.
03:39
I find the vector here, the second vector relative to c, which is going to be 3, negative 2 3, and 2 .3, and one third...