00:01
We're going to find the characteristic equation, eigenvalues, and bases for the eigenspaces.
00:07
So to find the characteristic equation, we want to solve the determinant of lambda identity minus the matrix.
00:21
Let's call it a.
00:26
So that's the determinant of lambda 0, 0, 0, lambda 0, 0, 0, lambda minus a.
00:38
Okay, so that's the determinant of lambda, negative 1, negative 1, negative 1, lambda, negative 1, negative 1, negative 1, lambda.
00:51
Okay, i'm going to expand along the first row.
00:53
We're going to be lambda times the determinant.
00:57
If i cross out this row and this column, i'm left with this 2 by 2, lambda, negative 1, negative 1, lambda.
01:06
Okay, now we alternate signs.
01:07
So it's going to be minus negative 1, so that's plus 1, times, and then the determinant, if i cross out this row and this column, i'm left with negative 1, negative 1, negative 1 lambda, okay, and then plus a negative 1, if i cross out that row and that column, i'm left with this 2 by 2, negative 1 lambda, negative 1, negative 1, okay, so this is lambda times the determinant of 2 by 2 is the product of the diagonal minus the product of the antideg, so it's going to be lambda squared, minus one.
01:47
Okay we have negative lambda minus one and we have one minus negative lambda will be plus lambda.
02:02
So this is lambda cubed minus lambda minus lambda minus one minus one minus lambda that's lambda cubed minus three lambda minus two.
02:17
Okay so possible integer roots are plus minus one and plus minus two.
02:24
I try one first.
02:26
It's going to be one minus three minus two.
02:28
That's not zero.
02:29
I try negative one.
02:30
It's going to be negative one plus three minus two is zero.
02:34
So negative one is the root.
02:36
I'm going to do synthetic division.
02:38
Negative one.
02:39
The coefficients are one.
02:41
There's no square, so that's a zero coefficient.
02:45
Negative three and negative two.
02:49
Now you bring down the one, multiply, add, add, multiply, add, multiply, add.
03:01
We got zero, that's good.
03:03
There should be a zero remainder.
03:04
So we know that the division out by lambda plus one leaves lambda squared minus lambda minus two.
03:17
Okay, and that's factorizable as lambda minus two lambda plus one.
03:26
So we found our characteristic equation.
03:28
We have lambda equals lambda plus one squared times lambda minus two.
03:50
The eigenvalues are the roots of this characteristic equation.
03:58
We have the eigenvalues negative one and two.
04:03
Now we want the eigenspaces.
04:09
These are the null spaces.
04:12
When i plug these lambda values into lambda identity minus eight.
04:18
Okay, so lambda identity minus a was this three by three here...