Question
Find the complete solution in radians of each equation.$$4 \sin ^{2} \theta+1=4 \sin \theta$$
Step 1
Step 1: First, we rewrite the given equation by subtracting 4 sine theta from both sides: $$ 4 \sin ^{2} \theta+1-4 \sin \theta=0 $$ This simplifies to: $$ 4 \sin ^{2} \theta-4 \sin \theta+1=0 $$ Show more…
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