00:01
We have that objective of problem, 2 .5 definite details of x, koss and x, x squared, sine, and x.
00:32
We have a dual u d b, ub minus integral d.
00:39
We have a degree x, cos, and x equals to x, y, n, sine, and x equals to x, n, n, x, x, x, x, and x, n, an x, and x, an x, x, and x, and x, and x, x x x x x x plus c we have the final thing we have find out it either e raised to the 1 minus 2 x cos n d x is equal to the to the part minus 2x by n, sign of nx, minus 2 by n square, rate as to 1 minus 2x, cos of nx, minus 4 by n squared entirely rate to the 1 minus 2x, course of nx, dx...