00:03
Okay, here in problem 79, we want to use the given magnitude of the vector, which is 3, and the given direction angle, in this case, theta, is 0.
00:16
And we want to use that information and put the vector in component form, and then, of course, sketch it.
00:23
And all you need to remember for this is this little formula to put a vector in component form.
00:31
When you're given its magnitude and the direction angle, it's going to be magnitude times the cosine of theta for your horizontal component, and then it's going to be magnitude times sine of theta for your vertical component.
00:49
So we're given everything we need, so it's literally just plugging right into that little formula, if you will.
00:56
So it's going to be three times the cosine of theta, which is zero, of course.
01:03
Put that in.
01:06
And then three times the sign of zero.
01:12
So you're going to have to remember your trigonometric ratios for some of these.
01:18
Cosign of zero is one.
01:20
And sine of zero is zero...