💬 👋 We’re always here. Join our Discord to connect with other students 24/7, any time, night or day.Join Here!
Get the answer to your homework problem.
Try Numerade Free for 7 Days
Like
Report
Find the critical numbers of the function.
$ F(x) = x^\frac{4}{5} (x - 4)^2 $
$$\begin{aligned}F(x) &=x^{4 / 5}(x-4)^{2} \Rightarrow \\F^{\prime}(x) &=x^{4 / 5} \cdot 2(x-4)+(x-4)^{2} \cdot \frac{4}{5} x^{-1 / 5}=\frac{1}{5} x^{-1 / 3}(x-4)[5 \cdot x \cdot 2+(x-4) \cdot 4] \\&=\frac{(x-4)(14 x-16)}{5 x^{1 / 5}}=\frac{2(x-4)(7 x-8)}{5 x^{1 / 5}}\end{aligned}$$
02:39
Wen Z.
Calculus 1 / AB
Calculus 2 / BC
Chapter 4
Applications of Differentiation
Section 1
Maximum and Minimum Values
Derivatives
Differentiation
Volume
Missouri State University
Oregon State University
University of Nottingham
Boston College
Lectures
01:11
In mathematics, integratio…
06:55
In grammar, determiners ar…
04:24
Find the critical numbers …
03:15
03:00
02:59
25-40 Find the critical nu…
02:36
03:19
07:53
06:30
00:46
02:54
Okay. We know that we can use the product. Roll off one GPAs FT one to find the derivative were fracturing out the two, as you can see. Okay, Now we have X minus form parentheses. Their first set, X Honest four equals to zero on the end, up with one of our critical numbers. X equals four. Next, we know that we can set seven x months. Eight equal to zero and we end up with X equals eight over seven as our second critical number. And then lastly, don't forget that we have zero as our third critical number because of the denominator.
In mathematics, integration is one of the two main operations in calculus, w…
In grammar, determiners are a class of words that are used in front of nouns…
Find the critical numbers of the function.$f(x)=5 x^{2}+4 x$
$ f(x) = 4 + \frac{1}{3}x…
Find the critical numbers of the function.$f(x)=x^{3}+x^{2}-x$
25-40 Find the critical numbers of the function.$$F(x)=x^{4 / 5}(x-4)^{2…
Find the critical numbers of the function.$f(x)=x^{2} e^{-3 x}$
Find the critical numbers of the function.$f(x)=2 x^{3}+x^{2}+2 x$
$ f(x) = x^{-2} \ln x $
$ f(x) = x^2 e^{-3x} $
$ g(x) = \sqrt[3]{4 - x^2…
Find the critical numbers of the function.$$g(x)=\sqrt[3]{4-x^{2}}$$
