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# Find the critical numbers of the function.$g(t) = | 3t - 4 |$

## $t=\frac{4}{3}$ is the only critical number

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### Video Transcript

Okay. The first thing we know is that three T minus four is greater equal to zero when tea is greater equal to 4/3. However, we know that the derivative G it prime of tea does not exist. It t equals 4/3. Also, the derivative is never zero. It's not possible. Therefore, we know that T equals 4/3 is our critical number.

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