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Find the critical numbers of the function.
$ g(y) = \frac{ y - 1}{ y^2 - y + 1} $
$$\begin{array}{l}g(y)=\frac{y-1}{y^{2}-y+1} \Rightarrow \\g^{\prime}(y)=\frac{\left(y^{2}-y+1\right)(1)-(y-1)(2 y-1)}{\left(y^{2}-y+1\right)^{2}}=\frac{y^{2}-y+1-\left(2 y^{2}-3 y+1\right)}{\left(y^{2}-y+1\right)^{2}}=\frac{-y^{2}+2 y}{\left(y^{2}-y+1\right)^{2}}=\frac{y(2-y)}{\left(y^{2}-y+1\right)^{2}}\end{array}$$
01:45
Wen Z.
Calculus 1 / AB
Calculus 2 / BC
Chapter 4
Applications of Differentiation
Section 1
Maximum and Minimum Values
Derivatives
Differentiation
Volume
Harvey Mudd College
Baylor University
University of Michigan - Ann Arbor
University of Nottingham
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