Question
Find the critical points, domain endpoints, and extreme values (absolute and local) for each function.$$y=x^{2 / 3}\left(x^{2}-4\right)$$
Step 1
The derivative of the function $y=x^{2 / 3}\left(x^{2}-4\right)$ is given by the product rule and the chain rule. The derivative is: $$y' = \frac{2}{3}x^{-1/3}(x^2-4) + x^{2/3}(2x)$$ Simplify this to get: $$y' = \frac{2}{3}x^{1/3}(x^2-4) + 2x^{5/3}$$ Show more…
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