00:01
Hello, students.
00:02
We need to write here x is equal to f.
00:04
We demand function.
00:05
We need to write here for this dx is equal to minus 400 divided by 0 .02 p minus 1 raised to power 3 and this must be dp.
00:16
So, we are going to integrate both sides.
00:19
We need to write here for this.
00:21
This is x is equal to minus 400 dp divided by 0 .02 p minus 1 raised to power 3.
00:31
So, basically 0 .02 p minus 1 is equal to t.
00:36
So, we are going to differentiate this.
00:38
This is 0 .02 dp is equal to dt.
00:42
We need to write here dp is dt divided by 0 .02.
00:46
This must be written as.
00:47
So, basically if i write here for this x value is minus 400 dt divided by 0 .02.
00:56
We need to write here for this t raised to power 3.
01:01
So, a raised to power minus m is 1 upon a raised to power m.
01:06
So, basically if i write here minus 400 t raised to power minus 3.
01:12
We need to write here dt divided by we need to write here for this.
01:18
This must be written as dt by dt by we need to write here.
01:26
So, basically this is something like this t raised to power minus 3 dt.
01:31
So, let's erase this to make it more clear dt divided by 0 .02...