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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79 Problem 80 Problem 81 Problem 82 Problem 83 Problem 84 Problem 85 Problem 86 Problem 87 Problem 88 Problem 88 Problem 90

Problem 35 Medium Difficulty

Find the derivative of the following functions.
$$y=w^{2} \sin w+2 w \cos w-2 \sin w$$

Answer

$w^{2}$ cos $w$

Related Courses

Calculus 1 / AB

Calculus: Early Transcendentals

Chapter 3

Derivatives

Section 5

Derivatives of Trigonometric Functions

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Derivatives

Differentiation

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Problem 16
Problem 17
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Problem 25
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Problem 28
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Problem 31
Problem 32
Problem 33
Problem 34
Problem 35
Problem 36
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Problem 39
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Problem 46
Problem 47
Problem 48
Problem 49
Problem 50
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Problem 53
Problem 54
Problem 55
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Problem 88
Problem 90

Video Transcript

So what? This problem were asked to find the derivative of this function outlined here in black. And because we have various functions being multiplied together, we have to use the product full so we'll start this by breaking down each term. So what? This first term we can define A as W squared and a prime therefore will be to W. And we consent e as sign of W and be prime as co sign w. So for this first term, we can then outline the product rule as to W times sign of W plus W Squared Times Co sign of W mm we can rewrite that, then is to w sign of W plus W squared Co sign W. And that's our first term. A second term, which will put in green can I meet outlined as a Equalling um, to W and e prime. Therefore equaling two and be equaling who sign of W and be prime would then be negative sign W. So for this second term, we would have the product full as to Times Co sign of W plus two w times negative sign of W. And again, we can simple finalize to co signed of you minus two w Sign of W in this third term, which will then putting Blue will have a you go into and then a prime would be zero and be equaling sign of W and be prime equal in co sign of W. So for this we'll have the product rule as zero times Sign W, which cancels out 20 was to Times Co sign of W. So now we have the individual product rules of each so we can combine all the terms together sits Huw sign of W plus W Squared Co sign of W plus to co sign of W minus two w sign of W minus two co sign W In this negative here comes from the original equation, and what you'll notice is that we have the same terms grouped together that just so happened to cancel out. So our final answer, therefore is W squared co sign of W

We have video lessons for 83.18% of the questions in this textbook
William Briggs, Lyle Cochran, Bernard Gillet

Calculus: Early Transcendentals

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