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Find the derivative of the function.$F(x) = (1 + x + x^2)^{99}$

99$\left(1+x+x^{2}\right)^{98}(1+2 x)$

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Catherine R.

Missouri State University

Caleb E.

Baylor University

Samuel H.

University of Nottingham

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Video Transcript

let's find the derivative of this function. And since it's a composite function with one function inside another, we're going to use a chain rule. So we start by finding the derivative of the outside function. And the outside function is the 99th power function. So we bring down the 99 we raise what's inside to the 98th. We subtract one to get the new power. Now we're gonna multiply by the derivative of the inside and the derivative of one plus X plus X squared is one plus two x So this is our derivative.

Oregon State University

Catherine R.

Missouri State University

Caleb E.

Baylor University

Samuel H.

University of Nottingham

Lectures

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