Problem

Find the derivative of the function. $ y = \di…

View

Problem 62 Hard Difficulty

Find the derivative of the function.

$ F(x) = \displaystyle \int^{2x}_{\sqrt{x}} \arctan t \, dt $

Name: find the derivative of the function fx displaystyle int2x_sqrtx arctan t dt
Uploaded: 2019-12-04
Duration: 1 min 5 s
Channel: Numerade
Description: Find the derivative of the function. $ F(x) = \displaystyle \int^{2x}_{\sqrt{x}} \arctan t \, dt $

Answer

$$
-\frac{1}{2 \sqrt{x}} \arctan (\sqrt{x})+2 \arctan (2 x)
$$

Discussion

You must be signed in to discuss.

Top Calculus 1 / AB Educators

Grace H.

Heather Z.

Oregon State University

Kristen K.

University of Michigan - Ann Arbor

Michael J.

Idaho State University

Watch More Solved Questions in Chapter 5

Problem 1

Problem 2

Problem 3

Problem 4

Problem 5

Problem 6

Problem 7

Problem 8

Problem 9

Problem 10

Problem 11

Problem 12

Problem 13

Problem 14

Problem 15

Problem 16

Problem 17

Problem 18

Problem 19

Problem 20

Problem 21

Problem 22

Problem 23

Problem 24

Problem 25

Problem 26

Problem 27

Problem 28

Problem 29

Problem 30

Problem 31

Problem 32

Problem 33

Problem 34

Problem 35

Problem 36

Problem 37

Problem 38

Problem 39

Problem 40

Problem 41

Problem 42

Problem 43

Problem 44

Problem 45

Problem 46

Problem 47

Problem 48

Problem 49

Problem 50

Problem 51

Problem 52

Problem 53

Problem 54

Problem 55

Problem 56

Problem 57

Problem 58

Problem 59

Problem 60

Problem 61

Problem 62

Problem 63

Problem 64

Problem 65

Problem 66

Problem 67

Problem 68

Problem 69

Problem 70

Problem 71

Problem 72

Problem 73

Problem 74

Problem 75

Problem 76

Problem 77

Problem 78

Problem 79

Problem 80

Problem 81

Problem 82

Problem 83

Problem 84

Problem 85

Problem 86

Video Transcript

Okay. You know, the first thing we can do is we can split this up. So we're splitting up the integral. Okay? Using the fundamental damn of calculus. We know G of X Prime is lower case G of X, which is equivalent to our pretend of acts. We have our 10 of X here, which means that we end up with negative one over to squirt of acts. Time's worth, 10 of squirt of max, plus two terms are tan of two acts cause we're just plugging in like that.

Amrita B.

Topics

Integrals

Integration

Calculus: Early Transcendentals

Chapter 5

Integrals

Section 3

The Fundamental Theorem of Calculus

Problem

Find the derivative of the function. $ y = \di…

Problem 62 Hard Difficulty

Find the derivative of the function.

$ F(x) = \displaystyle \int^{2x}_{\sqrt{x}} \arctan t \, dt $

Answer

$$
-\frac{1}{2 \sqrt{x}} \arctan (\sqrt{x})+2 \arctan (2 x)
$$

More Answers

Topics

Calculus: Early Transcendentals

Discussion

Top Calculus 1 / AB Educators

Grace H.

Heather Z.

Kristen K.

Michael J.

Calculus 1 / AB Bootcamp

Precalculus Review - Intro

Functions on the Real Line - Overview

Recommended Videos

Watch More Solved Questions in Chapter 5

Video Transcript

Topics

Calculus: Early Transcendentals

Top Calculus 1 / AB Educators

Grace H.

Heather Z.

Kristen K.

Michael J.

Calculus 1 / AB Bootcamp

Precalculus Review - Intro

Functions on the Real Line - Overview

Recommended Videos

Problem

Find the derivative of the function. $ y = \di…

Problem 62 Hard Difficulty

Find the derivative of the function. $ F(x) = \displaystyle \int^{2x}_{\sqrt{x}} \arctan t \, dt $

Answer

$$-\frac{1}{2 \sqrt{x}} \arctan (\sqrt{x})+2 \arctan (2 x)$$

More Answers

Topics

Calculus: Early Transcendentals

Discussion

Top Calculus 1 / AB Educators

Grace H.

Heather Z.

Kristen K.

Michael J.

Calculus 1 / AB Bootcamp

Precalculus Review - Intro

Functions on the Real Line - Overview

Recommended Videos

Watch More Solved Questions in Chapter 5

Video Transcript

Topics

Calculus: Early Transcendentals

Top Calculus 1 / AB Educators

Grace H.

Heather Z.

Kristen K.

Michael J.

Calculus 1 / AB Bootcamp

Precalculus Review - Intro

Functions on the Real Line - Overview

Recommended Videos

Find the derivative of the function.

$ F(x) = \displaystyle \int^{2x}_{\sqrt{x}} \arctan t \, dt $

$$
-\frac{1}{2 \sqrt{x}} \arctan (\sqrt{x})+2 \arctan (2 x)
$$