SOLVED:Find the derivative of the function. g(x) = \displaystyle \int^{3x}_{2x} \frac{u^2 - 1}{u^2 + 1} \, du \displaystyle \Biggl[ Hint: \int^{3x}_{2x} f(u) \, du = \int^0_{2x} f(u) \, du + \int^{3x}

Name: find the derivative of the function gx displaystyle int3x_2x fracu2 1u2 1 du displaystyle biggl hint
Uploaded: 2019-12-04
Duration: 56 s
Channel: Numerade
Description: Find the derivative of the function. $ g(x) = \displaystyle \int^{3x}_{2x} \frac{u^2 - 1}{u^2 + 1} \, du $ $ \displaystyle \Biggl[ Hint: \int^{3x}_{2x} f(u) \, du = \int^0_{2x} f(u) \, du + \int^{3x}_0 f(u) \, du \Biggr] $