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Find the derivative of the function.$y=\cot ^{2}(\sin \theta)$

$\frac{d y}{d x}=-2 \cot (\sin \theta) \cdot \csc ^{2}(\sin \theta) \cdot \cos \theta$

Calculus 1 / AB

Chapter 3

Derivatives

Section 5

The Chain Rule

Campbell University

Harvey Mudd College

University of Nottingham

Boston College

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this question asked us to find the derivative of the function. For this question, it's easiest to write it where everything is under the squared. It's just easiest to picture cause now we can see where exactly the expert is. So we know that we'd make that our new co fishing and onwards Okay, For this question we can use U substitution you is sign of data. What's inside R V is co tension of you and I are Why is vey square. So now we're different shooting. Using the chain rule, we have to V. That's the derivative of these squared times. Negative coast. He can't you terms co sign of data. Remember you is sign of data. Therefore, this simplifies to be negative, too. Co tangent Sign of Data Times CO. C can't squared sine of data Times CO sign of data. So basically, just remember to substitute and all of your values for U and V

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