💬 👋 We’re always here. Join our Discord to connect with other students 24/7, any time, night or day.Join Here!

Like

Report

Numerade Educator

Like

Report

Problem 39 Hard Difficulty

Find the derivative. Simplify where possible.
$ g(t) = t \coth \sqrt {t^2 + 1} $

Answer

$g^{\prime}(t)=c$ oth $\sqrt{t^{2}+1}-\frac{t^{2}}{\sqrt{t^{2}+1}}\left(\operatorname{csch}^{2} \sqrt{t^{2}+1}\right)$

Discussion

You must be signed in to discuss.

Video Transcript

Okay. We know that G Prime of tea. Using the product rule would be one times coach tangent h squared of t squared, plus one with tee times. This is a prevalent to co tangent H squirt of cheese squared, plus Juan minus t squared. Chris Eakin. Age squirt of cheese squared plus one over the squirt of t squared, plus one.