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Numerade Educator

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Problem 42 Easy Difficulty

Find the derivative. Simplify where possible.
$ y = x \tanh^{-1}x + \ln \sqrt {1 - x^2} $

Answer

$\tanh ^{-1} x$

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Video Transcript

we know that 10 h the negative one of you. In other words, inverse tangent is you prime over one month's you square. Therefore, we can write this as one nice x squared plus negative access just minus X over one minus X squared. And this simplifies to tangent h the negative one of acts. So that's the inverse.