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Section 3 .6 problem number 30, we're asked to take derivatives where we're using the chain rule.
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In several cases, you'll have to use other rules that you know.
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So i see two functions multiplied in both cases.
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I'm going to use the product rule as well.
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So y prime is going to be equal to, let's just say 1 over x.
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Now, what's the derivative of sine to the negative 5th? that's going to be negative 5, sine.
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So if you differentiate this, so to the negative 6x, and now the derivative of sine x is just cosine x.
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That's just the first part of the product rule.
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And now the next part will be, what's the derivative of 1 over x? that's minus 1 over x squared times sine negative 5th of x...