00:01
We're looking at y equals 3 t squared plus 12 over the square root of t minus 1 over t squared.
00:14
And so what i would do is i would like to write all of these with rational exponents.
00:21
And anytime you have a t in the denominator, it becomes a negative exponent and the square root is the same as to the one -half power.
00:29
And then t to the negative second power is equal to that.
00:32
And in this section, what we learn is that whenever we have a polynomial, or in this case, a sum of separate terms, some are different, we can just take the derivative of each piece, and then our answer is the sum are difference of each one.
00:48
So if i ask you for the derivative of 3t squared, i would expect you to know that it's 6t because you multiply the exponent by what's in front, and it's now to the first power because you subtract 1 from your exponent.
01:00
But as i move that negative 1 in half, negative 1 half, excuse me, half of 12 is 6, but has to be negative because you're multiplied by a negative...