00:01
We are looking at y equals the square root of x, which if you know that the square root is the same thing as to the one half power, which you should know if you're in calculus, this is made really easy.
00:13
Because all you need to know is that if you have a derivative of some independent variable to a constant, which is what's happening here.
00:20
One half is a constant.
00:22
You move that exponent in front and subtract one from that exponent.
00:27
So that's the theme and the problem.
00:30
When you're asked to find this derivative, i don't care if you write y prime.
00:34
I actually prefer d -y -d -x.
00:39
That's how i would do this problem.
00:41
You move that exponent in front, and then you subtract one from that exponent...