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Find the derivatives of the given functions.$$y=\frac{1}{1+4 x^{2}}-\tan ^{-1} 2 x$$
$\frac{d y}{d x}=\frac{-2(2 x+1)^{2}}{\left(1+4 x^{2}\right)^{2}}$
Calculus 1 / AB
Chapter 27
Differentiation of Transcendental Functions
Section 3
Derivatives of the Inverse Trigonometric Functions
Derivatives
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Okay, so before we, um, take the derivative of the following will start for rewriting this as negative exponents, sending attention in verse of X squared. What's for your fire of negative blood and I'll taking our evidence. We'll start with our power rule. That's negative. One vengeance inverse of X squared plus four but a par of negative one on minus one said It's negative, too. And then times derivative of tangent interest. That's one over one plus R Inside squared and in times conservative of X squared plus four. That's okay, so we get negative. Two x over. We can bring this sound, too or did not mean, but it's vengeance in verse of squares was four to the power of two times one plus X squared plus four Part two.
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