00:01
In the given question, we are told to find the determinant of the matrix a that is given over here.
00:08
The matrix is a 5 by 5 matrix and it has the elements 0 0 0 0 1, 0 0 2 0 1, 2 0 0, 0 4 0 0 0, then you have 0 0 0 3 0 and finally you have 5 0 0 0 0.
00:52
Now to find the determinant of this matrix, what you do is, let's expand this along the first row, right.
01:03
So when you take the first row, you can see that all the elements except this last element is non -zero.
01:11
So you can just take the expansion with respect to this element since all the elements will just give us 0 itself on multiplying.
01:20
So the way we expand this determinant is, you would take, let's say, what you do is, let's just write this as the determinant of a, let's remove this matrix sign and now what you do is, you take 1 and you take the minor of 1 and multiply it with 1, right.
01:54
So to find the minor of 1, what you do is, you delete the row that 1 is in, you delete the column that 1 is in and now the determinant of the remaining elements is what you call the minor of 1.
02:09
So over here, what you would have then is 1 times the minor of 1 will have the elements 0 0 2 0, 0 4 0 0, 0 0 0 3 and 5 0 0 0.
02:32
So again, we have now a 4 by 4 matrix.
02:36
So now, we are again expanding this with the first row.
02:44
One thing that you should notice is that we assign different signs to the different elements in a matrix when we expand.
02:51
So we assign plus to the first element, then we alternate the sign with each element.
02:57
So the second element is taken as minus, the third element is taken as plus, the fourth element is taken as minus, the fifth element will be taken as plus.
03:09
So these signs are just used or assigned when we expand this determinant, right.
03:16
So then in the case of this row, you have plus, minus, plus over here...