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# Find the differential of each function.(a) $y = \tan \sqrt t$(b) $y = \frac {1 - v^2}{1 + v^2}$

## (a) $d y=\frac{\sec ^{2} \sqrt{t}}{2 \sqrt{t}} d t$(b) $d y=\frac{-4 v}{\left(1+v^{2}\right)^{2}} d v$

Derivatives

Differentiation

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### Video Transcript

using the channel. We are d y equals, seek it squared square root of tea over to squirt of tea. And then don't forget the DT on the end. Okay, use the quotient. Rules off one G minus. FT one over G squared. So just over the germ meter squared. This simplifies to negative for V over one plus v squared squared times dv.

Derivatives

Differentiation

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