For part (a), we have $y=\tan \sqrt{t}$. The derivative of $\tan x$ is $\sec^2 x$ and the derivative of $\sqrt{t}$ is $\frac{1}{2\sqrt{t}}$. By the chain rule, the derivative of $y$ with respect to $t$ is $\frac{\sec^2 \sqrt{t}}{2\sqrt{t}}$.
For part (b), we
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