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Find the differential of each function.$$(a) y=\tan \sqrt{t}$$$$(b) y=\frac{1-v^{2}}{1+v^{2}}$$
A. $d y=\frac{\sec ^{2} \sqrt{t}}{2 \sqrt{t}} d t$B. $d y=\frac{-4 v}{\left(1+v^{2}\right)^{2}} \cdot d v$
Calculus 1 / AB
Chapter 2
DERIVATIVES
Section 8
Linear Approximations and Differentials
Derivatives
Differentiation
Applications of the Derivative
Campbell University
University of Michigan - Ann Arbor
University of Nottingham
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in this question, we are arm asking for the friend show so differently just you can see it's a natural way to return operated the curative So part A You like you close to the curative Focal Why Tom's DT So I will write in this way um, which is just the normal curative. So it's Seacon Square attempts route of tea. Well, terms 1/2 1/2 times unit of tea. Don't forget this TT in the end and the four probably do the same thing. Just be careful about the question rule so we can do this step by step. So for the question of where we take security for the numerator first and the we minus the second times for the second time we fixed the numerator and the taker duty of the denominator and Indiana. We divide the square off that you know miniter. Don't forget we have a TV in the end. This is the definition for the different show and, you know, have minus for weed from past the square, the square outside in the TV
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