00:02
Let's find the domain of the following vector valued function.
00:07
R of t equals cosine 2 t plus e to the square root of t, j, plus 2 over t k.
00:18
Well, the domain of a vector valued function is the intersection of the domains of all of the component functions.
00:27
So let's find the domains of each of the component functions.
00:29
First, we have the cosine of 2t.
00:36
The domain of the cosine of 2t is all real numbers.
00:40
There are no restrictions for what we can plug into t.
00:46
The second component function, e to the square root of t, i can plug anything into the exponential function, but to take the square root, i must have a non -negative number.
01:03
And so all non -negative numbers, 0 to infinity, is the domain of the second component function, because that's what i can use in the square root...