In this case, the denominator is $\sqrt{6-x}$, so we need to find the values of x that make $\sqrt{6-x}$ equal to zero.
To do this, we set $\sqrt{6-x}=0$ and solve for x. Squaring both sides of the equation, we get $6-x=0$. Solving for x, we find that $x=6$.
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