00:01
In this problem, we have a ring of charge, with linear charge, essentially lambda.
00:06
We're looking for the, and the origins at the center of that ring, and we're looking for the point, the electrophial at a point p, which is along the z -axis, and the radius of the ring is r, a little r.
00:18
Now, let's look at, and let's assume for a sake of argument that lambda is positive.
00:23
Anything we write, as long as we don't put absolute value signs around it, will work if lambda is negative.
00:28
We have negative charge.
00:29
So let's not worry about it.
00:32
So let's look at the two opposite dqs, infinitesimal charge elements.
00:39
And this would be r, which is equal to the square root, r squared plus e squared, and likewise in this side is totally symmetric, r.
00:54
Now everybody, just to remind you, everybody will, every dq will have a pair, will have a match.
01:01
E2 match, front and back match, everybody has a match.
01:04
Whatever i'm talking about here, whatever i have to talk about here will work for any pair, and so we'll be able to go through the whole sequence, whole set, infinite set of dqs.
01:14
I am going to need this angle theta in minutes, let me write it in.
01:17
All right.
01:18
So now let's look at the electric field due to the right dq.
01:23
That will be like this, and for the left, it'll be like this.
01:29
Notice anything in the horizontal? in this case, you think of this as the y axis and x coming out towards you and z.
01:37
The y components we cancel out, you only have z.
01:41
So what we're going to find, what we find then is that we have to just add up all the z components of all the dqs.
01:48
When we do our integration, we're just going to be adding up all the z components.
01:54
And before we get into doing that, we're going to need sine theta, z over capital r, which is r squared, or c squared.
02:07
Now we, dq, that's going to be lambda, times ds, ds, ds is an infinitesimal arc length, but this is a circle, lambda, r, d5.
02:19
Phi is the angle in the horizontal, taking you from one point in the circle all the way around every point.
02:26
It's got nothing to do with a point p.
02:29
This is for our integration.
02:32
Okay, so, d, e, z, this is the z component.
02:36
This is the electric field due to the right, dq, but this is the electric field due to the right and to the left.
02:46
This is the electric, the z component of electric field due to every dq.
02:55
So 1 over 4 pi epsilon 0, dq, capital r squared.
03:02
So that's going to be r squared plus z squared, time sign theta...