## 4.28 \mathrm{MeV}

### Discussion

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##### Andy C.

University of Michigan - Ann Arbor

##### Aspen F.

University of Sheffield

##### Jared E.

University of Winnipeg

### Video Transcript

in number 30. I'm defined the energy released in Alfa Decay of uranium to 38. So I'm gonna write my equation first. I start with uranium to 38 and they told me it's off. Okay, so I know that my one daughter will be an alpha particle and the other one just have a mass number off for less than a B 2 34 And it has to have two less protons. That's 90. And yes, that is Thor him. And they told me that. So now I'm just going to consider the masses back in the back. In appendix B, I looked at the mass for uranium to 38. It is 2 38 point 050 783 use, um, thorium. They told me here. They told me it was 2 34 0.43 and an Alfa particle. It's 4.2602 And these are all use atomic mess units. So I want to find the energy I find how much mass missing here. So basically have it right here. If I want to find the missing mass, it's going to be this minus these And when I do that, I get 0.5 one each one. You gonna convert that to the energy equivalent? I know that one. You is the same as 931 point 494 mega electron volts. So you canceled. And my energy is 4.82 mega electron volts.

University of Virginia
##### Andy C.

University of Michigan - Ann Arbor

##### Aspen F.

University of Sheffield

##### Jared E.

University of Winnipeg