Question
Find the entropy created when $100 \mathrm{~g}$ of ice melts at $0^{\circ} \mathrm{C}$ Compare with the entropy created when the same mass of water boils at $100^{\circ} \mathrm{C}$.
Step 1
The formula for heat added is $Q = mL_f$, where $m$ is the mass of the substance and $L_f$ is the latent heat of fusion. Substituting the given values, we get $Q = 100 \, \text{g} \times 334 \, \text{J/g} = 33400 \, \text{J}$. Show more…
Show all steps
Your feedback will help us improve your experience
Shahab Ullah and 53 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find the increase in entropy of 1.00 kg of ice originally at 0ºC that is melted to form water at 0ºC.
Find the change in entropy of $10.0 \mathrm{g}$ of water that freezes into ice at $0.0^{\circ} \mathrm{C}$. (Latent heat of fusion of ice $=334.4 \mathrm{kJ} \mathrm{kg}^{-1}$.)
Thermal properties of matter
Thermodynamics
Calculate the entropy change associated with melting $1.0 \mathrm{kg}$ of ice at $0^{\circ} \mathrm{C}$.
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD