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Find the equation for the ellipse that satisfies the given conditions:Ends of major axis $(\pm 3,0)$, ends of minor axis $(0, \pm 2)$
$ \frac{x^2}{9}+\frac{y^2}{4}=1$
Precalculus
Chapter 11
Conic Sections
Section 3
Circle
Introduction to Conic Sections
Harvey Mudd College
University of Michigan - Ann Arbor
Boston College
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in this problem, we are given that ends of media access is Plus -3 00. And the ends of the minor excesses zero comma plus minus two. This is major access. This is for my netflix. It is clearly seen from the coordinates that the media exists lies on the X axis because that's where the X coordinates. And since the minor axis has plus minus two on the y coordinate side, which means that the minor excesses that why access this is the Y axis and this is the X axis. So which means that you know the media access work. This is given us plus minus a comma zero is nothing but three and similarly be is nothing. But so we have the value of the N. B equation. Since the media excesses the X axis is X squared by a square plus. Why square by b squared equals to one, substituting this is X squared by a square nine plus Y squared by the square. Is food equals two? What? That's
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