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Find the equation of a circle satisfying the given conditions.Center: $(-8,-5) ;$ radius: $\sqrt{5}$
$(x+8)^{2}+(y+5)^{2}=5$
Precalculus
Algebra
Chapter 13
Nonlinear Functions, Conic Sections, and Nonlinear Systems
Section 2
The Circle and the Ellipse
Introduction to Conic Sections
An Introduction to Geometry
Functions
Systems of Equations and Inequalities
Campbell University
Oregon State University
Harvey Mudd College
Baylor University
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the center of a circle is at negative eight. Negative five and radius is the square root of five. In the equation of the circle is X minus negative eight or X plus eight squared plus y minus negative five or live plus five squared equals a spurt if I swear, which is just five.
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