Question
Find the equation of the circle that goes through the points $(1,3),(-8,0)$ and $(0,6)$
Step 1
We need to find \(h\), \(k\), and \(r\). Step 2: We can expand the equation of the circle: \[ x^2 - 2hx + h^2 + y^2 - 2ky + k^2 = r^2 \] Rearranging gives us: \[ x^2 + y^2 - 2hx - 2ky + (h^2 + k^2 - r^2) = 0 \] Let \(c = h^2 + k^2 - r^2\). The Show more…
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