Question
Find the equation of the line tangent to $y=f(x)$ at $x=1,$ where $f(x)=6 e^{5 x}+e^{-x^{2}}$
Step 1
The derivative of a function gives us the slope of the tangent line at any point. The derivative of $f(x)$ is given by $f'(x)=30 e^{5 x}-2x e^{-x^{2}}$. Show more…
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