00:01
In this exercise, we have two points that are given, and we're going to find the equation that passes through both of them.
00:06
Let's start by organizing.
00:08
Call x1 .3 and y1 .6, and likewise denote the second point by x2 and y2.
00:19
Now for our next step, let's calculate the slope m, which we know to be equal to y2 minus y1, divide by x2 minus x1.
00:29
Now we have to substitute in four different values.
00:34
So let's start with the first column where we have y2, indicated as a negative 8, and the x2, which is a 4.
00:42
Likewise, go to the second column that contains y1x1, y1 is 6, and x1 is negative 3.
00:51
So that's our format so far.
00:53
Next, let's begin simplifying.
00:55
In the numerator, we have altogether negative 14, and in the denominator we have 4.
01:01
4 plus 3...