00:01
In this exercise, we have two points provided, and our job here is to determine the equation of the line that will pass through both of them.
00:08
We'll start by organizing.
00:09
Let's call the first point x1y1 and call the second point x2y2.
00:18
Now, the first big step in this process is to calculate the slope of this line.
00:23
So, by formula, m is going to be y2 minus y1, divide by x2 minus x1, where x2 minus x1, where x2.
00:30
M denotes the slope.
00:33
So our format will look about like this and now we're ready to begin substituting.
00:37
In column 1, which deals with y2 and x2, y2 is a 1 and x2 is negative 3.
00:45
Now go to that column 2, which has y1 and x1, we set y1 to be negative 11 and x1 to be a positive 6.
00:56
So we drop in the quantities in that way.
00:59
Now when we simplify, we'll have 1 plus 11 in the numerator and a negative 9 in the denominator.
01:06
Let's simplify further...