00:01
Hi, we need to find the equation of the normal to the curve y is equal to 2x over x square plus 1 at this point 3 .0 .6.
00:12
So using the quotient rule, we can find dy, d x, d .x, dy, d x is equal to two times x square plus 1 d dx of x minus x times d d dx.
00:33
Of x squared plus 1 divided to x squared plus 1 square plus 1 square this gives us d y d x is equal to 2 times x squared plus 1 minus 2x squared divided 2x square plus 1 squared or finally dey d x is equal to 2 times 1 minus x squared divided to x squared plus 1 squared.
01:13
Now at the point 3, 0 .6, we can evaluate this, d .y, dx, is equal to 2 times 1 minus 3 square is 9, divided to x squared, 3 square is 9 plus 1 squared.
01:33
We are getting here minus 16 over 100 which is minus 4 over 25 now the normal gradient is equal to minus 1 divided to this divide x which is minus 4 25 we are getting here 25 fourth now this should pass through 3 0 .6 point, so y minus 0 .6 is equal to 25 fourth times x minus 3...