00:01
So in order to find point, just put x equal to minus 3 in this curve.
00:06
So y equal to minus 3 square would be 9 plus 4 into minus 3 minus 2.
00:14
So why would be 9 minus 12 minus 2? so why would be minus 5? so point would be minus 3 minus 5.
00:32
Now to find equation of normal, first we need to find slope of tangent, then we find slow of normal.
00:42
And then with the help of this point, we find equation of normal.
00:46
So, d .y upon d x will give us slow of tangent, that is d .x equal to 2x plus 4.
00:57
So dye upon dx at x equal to minus 3 will give us slow of tangent.
01:05
So that will be 2 minus 3 plus 4 will give you slope of tangent.
01:15
That would be minus 2.
01:18
Now slope of normal would be 1 upon 2 with the help of m1, m2 equal to minus 1.
01:32
So equation of normal equation of normal will be why 1.
01:40
Minus y1 equal to m times of x minus x1 so y minus point is minus 3 comma minus 5 so this will be plus 5 m is 1 by 2 and x minus x 1 so this will give us 3 so 2y plus 10 equal to x plus 3 so from here we can say that x minus 2 y equal to 7 is the equation of normal...