00:01
So we want to find the equation of our tangent line given x.
00:05
So this time we're given that our x value is equal to 2.
00:09
This a value here is 2.
00:11
So to find the equation of our line, we're going to need a point on that line.
00:17
So we can plug this x value into f of x to solve for y.
00:21
So why is it going to be equal to f of 2, which is equal to 5 over 2.
00:26
So we have that x1 comma y 1 is equal to 2 comma 5 over 2.
00:33
And now let's find our course onning slope.
00:35
So that's m is equal to the limit as x approaches 2 of f of x.
00:42
That's 5 over x minus f of a.
00:47
And this is all over x minus 2.
00:52
Okay, so let's view write our numerator into a single fraction.
00:55
So let's multiply this by x over x.
00:57
And this term by 2 over 2.
01:00
So we get that we have the limits as x approaches 2 of 10 minus 5.
01:06
X over 2x times x minus 2...