00:01
Okay, so we'll to find the equation of our tangent line.
00:04
So we're given our following function and a point on our line.
00:09
So this here is x1 comma y1.
00:14
So to find our equation of our line, we need this point as well as i slope.
00:18
Let's find our slope.
00:20
So we have f of x minus f of a.
00:23
So f of a, that's equal to f of this value here.
00:26
So that's 4.
00:27
So that's equal to the square bit of 4.
00:30
So we get 2.
00:30
So let's plug in our equation here.
00:33
So we have the limits as x approaches 4 of the square root of x minus 2, all over x minus 4.
00:44
So we want to solve for our following limits.
00:47
So let's multiply and divide by our conjugate...