Question
Find the equation of the tangent line to the given curve at the given point.$$\frac{x^{2}}{27}+\frac{y^{2}}{9}=1 \text { at }(3, \sqrt{6})$$
Step 1
To do this, we will use implicit differentiation. The given equation is: $$\frac{x^{2}}{27}+\frac{y^{2}}{9}=1$$ Differentiating both sides with respect to $x$, we get: $$\frac{2x}{27}+\frac{2yy'}{9}=0$$ Show more…
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