The given equation is in the general form of a circle: $(x-a)^2 + (y-b)^2 = r^2$. We can rewrite the given equation as:
$(x^2 - 8x) + (y^2 - 6y) = -20$
Now, complete the square for both x and y terms:
$(x^2 - 8x + 16) + (y^2 - 6y + 9) = -20 + 16 + 9$
$(x -
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